- 1: ReferenceError - 2: Inner

##### Answer: 1 The functions and variables declared in the function body cannot be referred from default value parameter initializers. If you still try to access, it throws a run-time ReferenceError(i.e, inner is not defined).

JS Coding Questions

#42🎯 Exercise💻 Code

JavaScript Coding Exercise 42

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javascript

1function outer(f = inner()) {
2
3function inner() {
4
5return "Inner";
6}
7}
8
9outer();

Choose the correct output:

ReferenceError

Inner

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