- 1: [empty, 'b', 'c', 'd'], empty, 3 - 2: [null, 'b', 'c', 'd'], empty, 3 - 3: [empty, 'b', 'c', 'd'], undefined, 4 - 4: [null, 'b', 'c', 'd'], undefined, 4

##### Answer: 3 The delete operator will delete the object property but it will not reindex the array or change its length. So the number or elements or length of the array won't be changed. If you try to print myChars then you can observe that it doesn't set an undefined value, rather the property is removed from the array. The newer versions of Chrome use empty instead of undefined to make the difference a bit clearer.

JavaScript Coding Exercise 7 | JSCodingQuestions.com

javascript

1var myChars = ["a", "b", "c", "d"];
2
3delete myChars[0];
4
5console.log(myChars);
6
7console.log(myChars[0]);
8
9console.log(myChars.length);

Choose the correct output:

[empty, 'b', 'c', 'd'], empty, 3

[null, 'b', 'c', 'd'], empty, 3

[empty, 'b', 'c', 'd'], undefined, 4

[null, 'b', 'c', 'd'], undefined, 4